Asked by Cam

A random sample of 50 students chosen from an elementary school with 400 students was found to have a mean allowance of $26 per week with a standard deviation of $8. Obtain a 98% confidence interval for the total amount of allowance money given to students in this school per week.
Answered by Kuai

26-2.33*8/sqrt((50)), 26+ 2.33*8/sqrt((50)),

= ( , ) ?
Answered by Cam
That's what I originally did but it's not one of the correct answers
Answered by Kuai
[ 23.37, 28.63]
Answered by Cam
$9,531 to $11,269


$9,347 to $11,453


$10,028 to $10,772


$9,414 to $11,386

Are my multiple choice
Answered by Kuai

mean 26(400) = $10400

Standard deviation = 8(400) = 3200
10400-+ 2.3263*3200/sqrt(50))


[$9,347, 11,453]
Answered by Cam
Thank you so much !
There are no AI answers yet. The ability to request AI answers is coming soon!