A random sample of 50 students chosen from an elementary school with 400 students was found to have a mean allowance of $26 per week with a standard deviation of $8. Obtain a 98% confidence interval for the total amount of allowance money given to students in this school per week.

Answer 1

26-2.33*8/sqrt((50)), 26+ 2.33*8/sqrt((50)),

= ( , ) ?

Answer 2

That's what I originally did but it's not one of the correct answers

Answer 3

[ 23.37, 28.63]

Answer 4

$9,531 to $11,269


$9,347 to $11,453


$10,028 to $10,772


$9,414 to $11,386

Are my multiple choice

Answer 5

mean 26(400) = $10400

Standard deviation = 8(400) = 3200
10400-+ 2.3263*3200/sqrt(50))

[$9,347, 11,453]

Answer 6

Thank you so much !