Asked by Andrea
I'm stuck with this problem.
h = -16t^2 + 312
the "t" is seconds after object released and h stands for height. We're suppose to set the equation to 0
so far this is what I have:
-16t^2 + 312 = 0
-8(2t^2+39)= 0
-8=0 can be disqualified but how do I factor out the 2t^2 + 39 = 0 and find the answer? Please help
h = -16t^2 + 312
the "t" is seconds after object released and h stands for height. We're suppose to set the equation to 0
so far this is what I have:
-16t^2 + 312 = 0
-8(2t^2+39)= 0
-8=0 can be disqualified but how do I factor out the 2t^2 + 39 = 0 and find the answer? Please help
Answers
Answered by
Steve
bzzt. Watch those signs. You meant to say
-8(2t^2-39)= 0
2t^2-39 = 0
2t^2 = 39
t^2 = 39/2
t = √(39/2)
-8(2t^2-39)= 0
2t^2-39 = 0
2t^2 = 39
t^2 = 39/2
t = √(39/2)
Answered by
Andrea
Sorry about the signs. The answer was suppose to be 2 seconds. That's what I'm not understanding. I'm coming out with what you have- I moved over the 2 and that left the t^2 = 39/2 but that doesn't come out to be two seconds which is suppose to be the answer
Answered by
Steve
well, surely you can see that
h(2) = -16(4) + 312 = 248
which is not zero. So, either 2 is wrong, or the equation is wrong.
h(t) = -16t^2 + 64
has h(2) = 0
h(2) = -16(4) + 312 = 248
which is not zero. So, either 2 is wrong, or the equation is wrong.
h(t) = -16t^2 + 64
has h(2) = 0
Answered by
Andrea
thank you I'll check back with my teacher.
Answered by
Vanessa
how do you solve x+y=2?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.