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Calculate the equilibrium constant for the weak acid, CH3CH2CO2H, if the aqueous solution of CH3CH2CO2H that has an initial concentration of 1.97E-2 M has a [H+] of 5.00E-4.
CH3CH2CO2H <=> CH3CH2CO2 + H
i know that to figure out the equilibrium constant it is kc = products/reactants
and i have to do something with the ICE table...but i don't know how to apply it...
CH3CH2CO2H <=> CH3CH2CO2 + H
i know that to figure out the equilibrium constant it is kc = products/reactants
and i have to do something with the ICE table...but i don't know how to apply it...
Answers
Answered by
DrBob222
Let's call CH3CH2COOH, just to save some time typing, HP.
HP ==> H+ + P^-
Ka = (H^+)(P^-)/(HP)
Initial concns:
(HP) = 1.97E-2
(H^+)= 0
(P^-) = 0
Equilibrium concns:
(H^+) = 5.00E-4
(P^-) = 5.00E-4
(HP) = 1.97E-2 - 5.00E-4
Plug those equilibrium values into the Ka expression and solve for K.
HP ==> H+ + P^-
Ka = (H^+)(P^-)/(HP)
Initial concns:
(HP) = 1.97E-2
(H^+)= 0
(P^-) = 0
Equilibrium concns:
(H^+) = 5.00E-4
(P^-) = 5.00E-4
(HP) = 1.97E-2 - 5.00E-4
Plug those equilibrium values into the Ka expression and solve for K.
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