Asked by katrina

What is the force exerted by a catcher's glove on a 0.15-kg baseball moving at 35 m/s that is stopped in 0.02 s?
Answered by Steve
the acceleration is -35m/s / .02s = -1750 m/s^2

F = ma = 0.15(-1750) = -262.5 N
Answered by Anonymous
Uubbu
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