Question

What is the force exerted by a catcher's glove on a 0.15-kg baseball moving at 35 m/s that is stopped in 0.02 s?

Answer 1

the acceleration is -35m/s / .02s = -1750 m/s^2

F = ma = 0.15(-1750) = -262.5 N

Answer 2

Uubbu