Asked by jason

How do I express this relationship in a language of variation?
I know how to do basic ones but this one is really advanced looking.

f=1/2L squarert T/u
Answered by jason
ah i forgot to clarify the 1/2L is being multiplied by the squareroot of T/u
Answered by Steve
f varies directly as L and the square root of T and inversely as the square root of u

f = kL√T/√u

If that's 1/(2L), then
f varies directly as √T and inversely as L and √u
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