solve:

2 ln e= ln sqrt of 7/x-2 ln e

what would be x?

2 answers

Assuming parentheses as shown below, and recalling that ln(e) = 1,
2 ln e= ln sqrt(7/(x-2)) ln e
2 = ln √(7/(x-2))
√7/(x-2)) = e^2
7/(x-2) = e^4
x-2 = 7e^-4
x = 2 + 7e^-4
Thanks Steve I have it now, But the answer checked out to be e^-4+ln sqrt 7
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