Asked by Barbara Passmore
Find the equation of a line that contains (-2, -2) and is perpendicular to y= -x+3
Answers
Answered by
Reiny
Since it is perpendicular its slope must be +1
equation:
y = x + b
but (-2,-2) lies on it, so
-2 = -2+b
b = 0
the new equation is y = x
equation:
y = x + b
but (-2,-2) lies on it, so
-2 = -2+b
b = 0
the new equation is y = x
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