Asked by muna
A 0.411 mol sample of PCl5(g) is injected into an empty 4.65 L reaction vessel held at 250 °C. Calculate the concentrations of PCl5(g) and PCl3(g) at equilibrium.kc=1.80 at 250c
Answers
Answered by
DrBob222
0.411mols/4.65L = 0.0884M
........PCl5 ==> PCl3 + Cl2
I......0.0884.....0......0
C.......-x........x......x
E.....0.0884-x....x......x
Substitute the E line into K expression and solve for x and 0.0884-x
........PCl5 ==> PCl3 + Cl2
I......0.0884.....0......0
C.......-x........x......x
E.....0.0884-x....x......x
Substitute the E line into K expression and solve for x and 0.0884-x
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.