Asked by zareen
first segment 12km(N60E),second segment 8km(N) and third segment 4km(N75W).Find the resultant displacement.
Answers
Answered by
Henry
Dr = 12km[30o] + 8km[90o] + 4km[165o]
X = 12*cos30+8*cos90+4*cos165 = 6.53 km
Y = 12*sin30+8*sin90+4*sin165 = 15.0 km
tan A = Y/X = 15/6.53 = 2.29709
A = 66.5o
Dr = Y/sin A = 15.0/sin66.5 = 16.4 km[66.5o].
X = 12*cos30+8*cos90+4*cos165 = 6.53 km
Y = 12*sin30+8*sin90+4*sin165 = 15.0 km
tan A = Y/X = 15/6.53 = 2.29709
A = 66.5o
Dr = Y/sin A = 15.0/sin66.5 = 16.4 km[66.5o].
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.