Question
first segment 12km(N60E),second segment 8km(N) and third segment 4km(N75W).Find the resultant displacement.
Answers
Henry
Dr = 12km[30o] + 8km[90o] + 4km[165o]
X = 12*cos30+8*cos90+4*cos165 = 6.53 km
Y = 12*sin30+8*sin90+4*sin165 = 15.0 km
tan A = Y/X = 15/6.53 = 2.29709
A = 66.5o
Dr = Y/sin A = 15.0/sin66.5 = 16.4 km[66.5o].
X = 12*cos30+8*cos90+4*cos165 = 6.53 km
Y = 12*sin30+8*sin90+4*sin165 = 15.0 km
tan A = Y/X = 15/6.53 = 2.29709
A = 66.5o
Dr = Y/sin A = 15.0/sin66.5 = 16.4 km[66.5o].