Question
Use the following dates to compute the ALOS and median LOS and range. The discharge date is July 2nd (non-leap year). Round the ALOS to one decimal place.
Admission Date LOS
1-2 January = 29; February = 28; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 181
1-10 January = 21; February = 28; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 173
2-8 February = 20; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 144
2-10 February = 18; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 142
2-26 February = 2; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 126
3-1 March = 30; April = 30; May = 31; June = 30; July = 2; Total = 123
3-6 March = 25; April = 30; May = 31; June = 30; July = 2; Total = 118
3-12 March = 19; April = 30; May = 31; June = 30; July = 2; Total = 112
3-15 March = 16; April = 30; May = 31; June = 30; July = 2; Total = 109
4-1 April = 29; May = 31; June = 30; July = 2; Total = 92
4-15 April = 15; May = 31; June = 30; July = 2; Total = 78
5-3 May = 28; June = 30; July = 2; Total = 60
5-5 May = 26; June = 30; July = 2; Total = 58
5-6 May = 25; June = 30; July = 2; Total = 57
5-18 May = 13; June = 30; July = 2; Total = 45
6-17 June = 13; July = 2; Total = 15
6-29 June = 1; July = 2; Total = 3
7-1 July 2; Total = 1
Okay I need help with this I want to make sure If I am doing this right or not. This is statistics for healthcare.
I calculated the median as 109+92=201/2=100.5
Range-180
I am confused on how I go about figuring out the ALOS (average length of stay) for this problem. Can anyone help me figure this out. I would appreciate it. Thank you.
Admission Date LOS
1-2 January = 29; February = 28; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 181
1-10 January = 21; February = 28; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 173
2-8 February = 20; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 144
2-10 February = 18; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 142
2-26 February = 2; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 126
3-1 March = 30; April = 30; May = 31; June = 30; July = 2; Total = 123
3-6 March = 25; April = 30; May = 31; June = 30; July = 2; Total = 118
3-12 March = 19; April = 30; May = 31; June = 30; July = 2; Total = 112
3-15 March = 16; April = 30; May = 31; June = 30; July = 2; Total = 109
4-1 April = 29; May = 31; June = 30; July = 2; Total = 92
4-15 April = 15; May = 31; June = 30; July = 2; Total = 78
5-3 May = 28; June = 30; July = 2; Total = 60
5-5 May = 26; June = 30; July = 2; Total = 58
5-6 May = 25; June = 30; July = 2; Total = 57
5-18 May = 13; June = 30; July = 2; Total = 45
6-17 June = 13; July = 2; Total = 15
6-29 June = 1; July = 2; Total = 3
7-1 July 2; Total = 1
Okay I need help with this I want to make sure If I am doing this right or not. This is statistics for healthcare.
I calculated the median as 109+92=201/2=100.5
Range-180
I am confused on how I go about figuring out the ALOS (average length of stay) for this problem. Can anyone help me figure this out. I would appreciate it. Thank you.
Answers
You're right.
The total LOS divided by the number of patients discharge is the average length of stay (ALOS).
The total LOS divided by the number of patients discharge is the average length of stay (ALOS).
Okay so my total is 1637 divided by 18 patients is it? 1637/18=90.9 round that off to one decimal place =91.0 days is that correct??
I confuse myself with all of this. Thanks so much for your help Kuai!
I confuse myself with all of this. Thanks so much for your help Kuai!
Rainfall Data
Month Rainfall (cm)
January 4.3
February 3.9
March 4.0
April 5.0
May 2.9
June 3.2
July 1.9
August 2.0
September 3.7
October 3.8
November 4.2
December 4.9
What is the mode of the data in the rainfall table?
Responses
A 3.653.65
B 3.13.1
C no modeno mode
D 5.05.0
E 3.7
Month Rainfall (cm)
January 4.3
February 3.9
March 4.0
April 5.0
May 2.9
June 3.2
July 1.9
August 2.0
September 3.7
October 3.8
November 4.2
December 4.9
What is the mode of the data in the rainfall table?
Responses
A 3.653.65
B 3.13.1
C no modeno mode
D 5.05.0
E 3.7
C, no mode.
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