Asked by JAYZ
A potter’s wheel of radius 53.13 cm and mass 106.4 kg is freely rotating at 47.1 rev/min. The potter can stop the wheel in 5.65 s by pressing a wet rag against the rim and exerting a radially inward force of 66.2 N.
What is the angular acceleration of the wheel?
What is the angular acceleration of the wheel?
Answers
Answered by
Damon
The only information of any use in this lengthy paragraph is:
wheel stops from 47.1 rev/min in 5.65 sec
we want radians and seconds
47.1 rev/min * 2 pi rad/rev * 1 min/60 s
= 4.93 radians/second
acceleration = change in velocity/change in time
= 4.93 rad/s / 5.65 s
= .873 radians/second^2
wheel stops from 47.1 rev/min in 5.65 sec
we want radians and seconds
47.1 rev/min * 2 pi rad/rev * 1 min/60 s
= 4.93 radians/second
acceleration = change in velocity/change in time
= 4.93 rad/s / 5.65 s
= .873 radians/second^2
Answered by
Damon
Oh, and the answer is negative (deacceleration)
Answered by
JAYZ
yea i had the answer but forgot the negative, thanks man! really appreciate it!
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