Ask a New Question

Asked by Kirandeep

The area of a rectangle is y^2 +6y-27.
A) find length and width of the rectangle.
B)find perimeter of this rectangle.
11 years ago

Answers

Answered by bobpursley
factor area
(y+9)*(y-3)

length: y+9
width: y-3

perimeter=2L+2W
11 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

The area of a rectangle is 189. The width is 2 meter longer than 1/3 the length. find the length and... The area of a rectangle is 2X squared minus X -21 squared meters.The width is 2X -7 squared meters.... what is the area of a rectangle mesuring 11 by 7 The area of a rectangle is 21 ft^2,and the length of the rectangle is 1 ft less than twice the wid... A rectangle has an area of 45 square centimeters and a length of 10 centimeters. What is the width... The area of a rectangle is 12 square feet. What are all the possible integer values of its perimete... what is the area of a rectangle with a length that is 5 more than triple the width? what is the area of a rectangle with a length of 2 meters? If the area of a rectangle is 2,460 square inches, what are its dimensions? What is the area of a rectangle with base 10in. and height 13 in.?
Submit Your Answer

Question

The area of a rectangle is y^2 +6y-27.
A) find length and width of the rectangle.
B)find perimeter of this rectangle.

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use