Asked by Sanya
Write the Ka reaction for formic acid, HCO2H, and for methylammonium ion, CH3NH+
3 . How do I approach this?
3 . How do I approach this?
Answers
Answered by
DrBob222
The question isn't clear to me but I assume you are looking for TWO separate Ka reactions.
HCO2H + H2O ==> H3O^+ + HCO2^-
Ka = (H3O^+)(HCO2^-)/HCO2H) = ?
CH3NH3^+ + H2O ==> H3O^+ + CH3NH2
Ka for CH3NH2^+ = (Kw/Kb for CH3NH2) = (H3O^+)(CH3NH2)/(CH3NH3^+)
HCO2H + H2O ==> H3O^+ + HCO2^-
Ka = (H3O^+)(HCO2^-)/HCO2H) = ?
CH3NH3^+ + H2O ==> H3O^+ + CH3NH2
Ka for CH3NH2^+ = (Kw/Kb for CH3NH2) = (H3O^+)(CH3NH2)/(CH3NH3^+)
Answered by
Sanya
Thank you Dr. Bob! :)I had that but it seemed too simple to be true. I didn't have my text to verify.
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