How many grams of Ni(OH)2 are produced from the reaction of 25.0mL of a 0.600M NaOH solution? NiCl2(aq)+2NaOH(aq)→

Question

Ni(OH)2(s)+2NaCl(aq)

Answer 1

mols NaOH = M x L = ?
Use the coefficients in the balanced equation to convert mols NaOH to mols Ni(OH)2
Now convert mols Ni(OH)2 to g. g = mols x molar mass.

Answer 2

NiCl2(aq) + 2NaOH(aq) → Ni(OH)2(s) + 2NaCl(aq)
First get the number of moles of NaOH. Recall that molarity is moles of solute per liter of solution:
M = n / V
Getting n,
n = MV
n = (0.6)(0.025)
n = 0.015 mol NaOH
To get the mol Ni(OH)2, we multiply the mol of NaOH to the ratio found from the reaction. From the reaction, for every 1 mol of Ni(OH)2 produced, 2 mol NaOH are consumed.
0.015 mol NaOH * 1 mol Ni(OH)2 / 2 mol NaOH = 0.0075 mol Ni(OH)2
Finally, to get the mass of Ni(OH)2, multiply 0.0075 mol by the molar mass of Ni(OH)2.

Hope this helps :3

Answer 3

1.25 g Ni(OH)2