Asked by ellie

hello i am having trouble writing these two ionic equations. could someone explain to me how to do that? 1.)K2SO4(aq) and Na2CO3(aq).Write the ionic equation.
2.)RbCl(aq) and KOH(aq).Write the ionic equation.

Answers

Answered by DrBob222
K2SO4(aq) + Na2CO3(aq) ==> 2K^+(aq) + SO4^2-(aq) + 2Na^+(aq) + CO3^2-(aq)


The second one is done the same way. If there is
1. no gas
2. no ppt
3. no slightly ionized product
then you write a simple mixing o the ions. If one of the 3 occurs, there will be a reaction and you can write a net ionic equation.
For example,
AgNO3(aq) + NaCl(aq)==> AgCl(s) + NaNO3(aq) for which the net ionic equation is
Ag^+(aq) + Cl^-(aq) ==> AgCl(s)
Answered by Genious
2. Rb and K are in the same column 1 (group 1) which is soluble; meaning that they dissolved in a solution or solvent. The answer is just "noreaction" for the Ionic and Net equation
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