Question

i need to use the quadratic formula 2 solve these 4 questions:

1. x(squared)-6x+4=0
2. t(squared)+4t-2=0
3. 3x(squared)+10X+5=0
4. 2x=7-x(squared)

I just can't seem 2 get the right answer!

Answer 1

x^2 - 6 x + 4 = 0

x = [ 6 +/- sqrt (36 -16) ] / 2

x = 3 +/- 2 sqrt (9 - 4)

x = 3 +/-2 sqrt (5)
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t^2 + 4 t - 2 = 0

t = [ -4 +/- sqrt (16 + 8) ] / 2

t = [-4 +/- 2 sqrt (4+2) ] / 2

t = -2 +/- sqrt (6)
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3 x^2 + 10 x + 5 = 0

x = [ -10 +/- sqrt (100 - 60) ]/6

x = [ -10 +/- 2 sqrt (25 - 15) ]/6

x = -5/3 +/- (1/3) sqrt (10)

Answer 2

what is this