Asked by Jill
A car starts rolling down a l-in-4 hill (l-in-4 means that for each 4 m traveled along the road, the elevation change is 1 m). How fast is it going when it reaches the bottom after traveling 55 m? (a) Ignore friction, (b) Assume an effective coefficient of friction equal to 0.10.
and also
Two boxes, mx — 1.0 kg with a coefficient of kinetic fric tion of 0.10, and m2 = 2.0 kg with a coefficient of 0.20, are placed on a plane inclined at 9 = 30°. (a) What acceleration does each box experience? (b) If a taut string is connected to the boxes (Fig. 4-64), with m2 initially farther down the slope, what is the acceleration of each box? (c) If the initial configuration is reversed with m\ starting lower with a taut string, what is the acceleration of each box?
and also
Two boxes, mx — 1.0 kg with a coefficient of kinetic fric tion of 0.10, and m2 = 2.0 kg with a coefficient of 0.20, are placed on a plane inclined at 9 = 30°. (a) What acceleration does each box experience? (b) If a taut string is connected to the boxes (Fig. 4-64), with m2 initially farther down the slope, what is the acceleration of each box? (c) If the initial configuration is reversed with m\ starting lower with a taut string, what is the acceleration of each box?
Answers
Answered by
bobpursley
first:
the normal component of weight is mg*sqrt(15/16)
friction then is mg*sqrt(15/16)*mu
So going 55m, work is mg*sqrt(15/16)*.1*55
final KE=initialPE-workdone.
second question
I dontknow the incline.
the normal component of weight is mg*sqrt(15/16)
friction then is mg*sqrt(15/16)*mu
So going 55m, work is mg*sqrt(15/16)*.1*55
final KE=initialPE-workdone.
second question
I dontknow the incline.
Answered by
Jill
the incline is 30 degrees
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.