Asked by Uri
Find the LCD of the ration expressions:
A) [9x/(x^2-z^2)] [3/(x^2-2xz+z^2)]
B) [x/(x^2-64)] [2/(40-5x)] [7/x]
A) [9x/(x^2-z^2)] [3/(x^2-2xz+z^2)]
B) [x/(x^2-64)] [2/(40-5x)] [7/x]
Answers
Answered by
Jai
A. Factors of denominators:
(x^2-z^2) = (x+z)(x-z)
(x^2-2xz+z^2) = (x-z)(x-z)
Thus, LCD : (x+z)(x-z)(x-z)
B. Factors of denominators:
(x^2-64) = (x-8)(x+8)
(40-5x) = -5(x-8)
x = x
Thus LCD : -5x(x-8)(x+8)
Hope this helps :3
(x^2-z^2) = (x+z)(x-z)
(x^2-2xz+z^2) = (x-z)(x-z)
Thus, LCD : (x+z)(x-z)(x-z)
B. Factors of denominators:
(x^2-64) = (x-8)(x+8)
(40-5x) = -5(x-8)
x = x
Thus LCD : -5x(x-8)(x+8)
Hope this helps :3
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