Asked by Tracy
                9w-w^3
2a^2+1+3a
            
        2a^2+1+3a
Answers
                    Answered by
            Kuai
            
    -w (w^2-9) 
-w(w-3)(w+3)
2a^2 +3a +1
(2a+ 1)(a+1)
    
-w(w-3)(w+3)
2a^2 +3a +1
(2a+ 1)(a+1)
                    Answered by
            Tracy
            
    Thank you. Can you please do this in the ac method form?
    
                    Answered by
            Tracy
            
    I need to know how to factor these in A-C method form
2a^2+1+3a
9w-w^3
    
2a^2+1+3a
9w-w^3
                    Answered by
            Steve
            
    The w one needs no ac method
2a^2 + 3a + 1
You need factors of 2*1 which add to 3, so
2a^2 + 2a + a+1
2a(a+1) + (a+1)
(2a+1)(a+1)
    
2a^2 + 3a + 1
You need factors of 2*1 which add to 3, so
2a^2 + 2a + a+1
2a(a+1) + (a+1)
(2a+1)(a+1)
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