-w (w^2-9)
-w(w-3)(w+3)
2a^2 +3a +1
(2a+ 1)(a+1)
9w-w^3
2a^2+1+3a
4 answers
Thank you. Can you please do this in the ac method form?
I need to know how to factor these in A-C method form
2a^2+1+3a
9w-w^3
2a^2+1+3a
9w-w^3
The w one needs no ac method
2a^2 + 3a + 1
You need factors of 2*1 which add to 3, so
2a^2 + 2a + a+1
2a(a+1) + (a+1)
(2a+1)(a+1)
2a^2 + 3a + 1
You need factors of 2*1 which add to 3, so
2a^2 + 2a + a+1
2a(a+1) + (a+1)
(2a+1)(a+1)