Asked by Marcos
ln sqrt(x-8)= 5
I would like help to solve this what i did was to take away the square root i squared both sides coming up with
(ln sqrt(x-8))^2= (5)^2
ln(x-8)=25
am i alowed to do this with ln in the equation?
then i subtract 8 from both sides
ln x = 17
e^(ln x)= e^17
e cancels out ln leaving with
x=e^17
this is not right the real answer is
x = 8 + e^10 on math-way but how?
thanks
I would like help to solve this what i did was to take away the square root i squared both sides coming up with
(ln sqrt(x-8))^2= (5)^2
ln(x-8)=25
am i alowed to do this with ln in the equation?
then i subtract 8 from both sides
ln x = 17
e^(ln x)= e^17
e cancels out ln leaving with
x=e^17
this is not right the real answer is
x = 8 + e^10 on math-way but how?
thanks
Answers
Answered by
Steve
Not even close.
ln√(x-8) = 5
1/2 ln(x-8) = 5
ln(x-8) = 10
x-8 = e^10
x = 8+e^10
ln√(x-8) = 5
1/2 ln(x-8) = 5
ln(x-8) = 10
x-8 = e^10
x = 8+e^10
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