Asked by Angie
A rectangle has a perimeter of 98 feet. The lenght is 8 feet longer than double the width. Find each Dimension.
Answers
Answered by
Reiny
let the width be x
"The lenght is 8 feet longer than double the width" ----> length = 2x+8
Now isn't 2(x + 2x+8) = 98 ?
Solve this little equation.
"The lenght is 8 feet longer than double the width" ----> length = 2x+8
Now isn't 2(x + 2x+8) = 98 ?
Solve this little equation.
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