Question

A 250.0 mL sample of 0.200 M aqueous aluminum chloride is mixed with 100.0 mL of 0.200 M aqueous sodium hydroxide.

I need help calculating the concentration of Na...

Check these concentrations:

OH= 0M since is the LR

Al= 0.124M

Na=??

Cl= 0.429M
(Na^+) = (NaOH)
mols NaOH = M x L
(NaOH) = (M NaOH x L NaOH/total volume) = 0.200 x 0.100/0.350) =?
The others look ok to me.

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