Which equation has the complex number 4-3i as a root?
(1) x^2+6x-25=0
(2) x^2-6x+25=0
(3) x^2+8x-25=0
(4) x^2-8x+25=0
I have no clue how to do it!!!PLEASE HELP!!!Please guide by step by step!!THANKS A LOT~!!!!
2 answers
Look at the serds. To get a serd that is negative, you have to have a or c negative. That means only 1 or 3 can be correct. Now, which yields sqrt (b^2-4ac) to be 6i ?
I still don't get it
1 answer