Ask a New Question

Asked by CHRIS

z=x(1-i)+24(-2+i) , x is a real number.
if z^2 is a negative real number what is x?
12 years ago

Answers

Answered by Steve
z^2 = 1728-48x - 2(x^2-72x+1152)i

So, if z^2 is real,

x^2-72x+1152 = 0
(x-24)(x-48)

Since z^2 < 0, 1728-48x < 0, so x=48
12 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

What is the real value of x in the equation log(subscript 2)24-log(subscript 2)3=log(subscript 5)x?... I'm sorry, I know that you really can't give out answers but I've been trying to figure this out for... i really need some help, i really appreciate all yalls help. Consider the function F(x)=2x^2-5x+5... what wud have been another really good Canadian song sung at the Olympics? Is this one good: Sa... HOW DO I COME UP WITH THE REAL NUMBERS FOR X-2Y=200 THE REAL NUMBERS FOR X AND Y Given that a and b are real numbers such that the follwoing quadratic equation x^2+(a+6i)x+b+12i=0 h... f(x)=x ^2 +bx+c , b and c real .Find the minimum of (max|f(x)|)for x∈[−10,10]? what is the real value of x in the equation log² 24 – log³ 3 = log5 x I am very confused with... Zombies are real, but not real on tv. True or false? ima keep it real wit u i still got feelings toward u but its like i dont really wanna gpo dat way ag...
Submit Your Answer

Question

z=x(1-i)+24(-2+i) , x is a real number.
if z^2 is a negative real number what is x?

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use