Asked by CHRIS
z=x(1-i)+24(-2+i) , x is a real number.
if z^2 is a negative real number what is x?
if z^2 is a negative real number what is x?
Answers
Answered by
Steve
z^2 = 1728-48x - 2(x^2-72x+1152)i
So, if z^2 is real,
x^2-72x+1152 = 0
(x-24)(x-48)
Since z^2 < 0, 1728-48x < 0, so x=48
So, if z^2 is real,
x^2-72x+1152 = 0
(x-24)(x-48)
Since z^2 < 0, 1728-48x < 0, so x=48
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