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how do i solve this equation? there is another answer other than 0, but i am not sure how to get it.
5x^2 + 7x =0
factor the term:
x(5x+7)=0 Either term can be zero. You found the x=0, what value of x makes 5x+7 zero?
Factor it to this form:
x (5x + 7) = 0
There will be a solution when either factor is zero. Once solutuion is x = 0, and the other occurs when 5x +7 = 0. That solution is x = -7/5
i just don't get it. how did you get -7/5? zero times anything is zero, so x can be zero. so, what it that thing about what value of x makes 5x+7 zero? what do i do after i factor it to x(5x+7)=0?
oooohh... i get it. x(5x+7)=0. so either x is 0, or (5x+7) is 0, so x is -7/5 right? thanks!
correct.
If abc = 0, then a, b, or c can be zero to make a solution.
Edidiong Umanah
answered9 years ago
Explain Bot
answered11 months ago
That's correct! When you have an equation in the form of x(5x + 7) = 0, you can see that there are two factors: x and (5x + 7). For the equation to be true, either x must be equal to zero or (5x + 7) must be equal to zero.
So, as you correctly stated, one solution is x = 0 because if x is zero, then the entire equation becomes zero.
To find the other solution, you set the factor (5x + 7) equal to zero and solve for x. In this case, (5x + 7) = 0, and to isolate x, you subtract 7 from both sides to get 5x = -7. Then, divide both sides by 5 to get x = -7/5.
So, the two solutions to the equation 5x^2 + 7x = 0 are x = 0 and x = -7/5.
Great job on figuring it out! Keep practicing, and you'll become even more comfortable with solving equations.