molescompound*Heatcombutstion=Heatcapacity*deltaTemp
1.365/102.90 * 3599.0 =7.819*Heatcapcity
solve for heat capacity. Pay attention to units.
At constant volume, the heat of combustion of a particular compound is –3599.0 kJ/mol. When 1.365 g of this compound (molar mass = 102.90 g/mol) was burned in a bomb calorimeter, the temperature of the calorimeter (including its contents) rose by 7.819 °C. What is the heat capacity (calorimeter constant) of the calorimeter?
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