Question

Sodium reacts with chlorine gas according to the reaction:\

2 Na (s) + Cl2 (g) ---> 2 NaCl (s)

What volume of chlorine gas, measured at 687 mmHg and 313 K, is required to form 275 g of NaCl?

Answer 1

Convert 275 g NaCl to mols.

Convert mols NaCl to mols Cl2 using the coefficients in the balanced equation.

Use PV = nRT to solve for V of Cl2 at the stated conditions.

Answer 2

Okay...

1) 275 g NaCl ----> 4.71 mol NaCl

2) Next, 4.71 mol NaCl * 1Cl2/2 NaCl = 2.36 mol Cl

3) V= nRT/P

v= (2.36 mol)(0.0821 L atm/K Mol)(313K)/687mmHg = 0.0883 L

Final answer: v = 0.0883 L

Answer 3

All of your calculations and numbers look good until the last step. Pressure in PV = nRT must go in in units of atmospheres. Change by 687/760 = ?? atm.

Answer 4

So, if I convert mmHg to atm I get .904 atm. When I plug that into the equation, the final answer is 67.1 L?

Answer 5

right