Question
Find the second derivative of the function.
f(x)= (3x^3+7)^7
f(x)= (3x^3+7)^7
Answers
Steve
no problem
f' = 7(3x^3+7)^6 * 9x^2
= 63x^2 (3x^3+7)^6
f" = 126x(3x^3+7)^6 + 63x^2 * 6(3x^3+7)^5 * 9x^2
= 126x(3x^3+7)^5 (3x^3+7 + 27x^3)
= 126x(3x^3+7)^5 (30x^3+7)
f' = 7(3x^3+7)^6 * 9x^2
= 63x^2 (3x^3+7)^6
f" = 126x(3x^3+7)^6 + 63x^2 * 6(3x^3+7)^5 * 9x^2
= 126x(3x^3+7)^5 (3x^3+7 + 27x^3)
= 126x(3x^3+7)^5 (30x^3+7)
cal
I have these ans choices:
A. f= 63x(7+3x^3)^5 (14+60x^3)
B. f= 63x(7+3x^3)^5 (14+63x^3)
C. f= 63x(7+3x)^5 (14+63x^3)
D. f= 63x(7+3x^3)^5 (14-60x^3)
A. f= 63x(7+3x^3)^5 (14+60x^3)
B. f= 63x(7+3x^3)^5 (14+63x^3)
C. f= 63x(7+3x)^5 (14+63x^3)
D. f= 63x(7+3x^3)^5 (14-60x^3)
Steve
Come on, guy. move the 2 from 126 into the last term. Algebra I, here.
Steve
good man.
no idea why they didn't factor out the 2 as well.
no idea why they didn't factor out the 2 as well.