Question

Given a rectangular object with dimensions 2cm by 22cm, we want to increase the length of the smaller dimension and decrease the length of the larger dimension by Xcm each.
If the the diagonal has to be kept less than (sqrt360)cm in length, the range of X can be expressed as a<X<b. What are the values of a and b?

Answer 1

(2+x)^2 + (22-x)^2 < 360
4 < x < 16

Answer 2

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