Asked by Nate

An 80.0 g sample of a gas was heated from 25 degree C to 225 degree C. During this process, 346 J of work was done by the system and its internal energy increased by 7495 J. What is the specific heat of the gas?
J/(g∗C)
Answered by DrBob222
I believe this is
E2-E1 = delta E = q+w
dE = 7495
w is -346
q = 7495+346 = ?
Then q = mass gas x specific heat gas x (Tfinal-Tinitial)
Solve for specific heat gas.
Answered by Anna
you did not solve the whole problem!
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