What units do you want this. This often is reported in mg/L.
0.4078g PbCO3 x (molar mass Pb^2+/molar mass PbCO3) = ?g Pb and convert that to mg. That is mg/100 mL, convert to mg/L.
Pb^2+ =
The concentration of Pb2+ in a sample of wastewater is to be determined by using
gravimetric analysis. To a 100.0-mL sample of the wastewater is added an excess of
sodium carbonate, forming the insoluble lead (II) carbonate (267.2092 g/mol) according to
the balanced equation given below. The solid lead (II) carbonate is dried, and its mass is
measured to be 0.4078 g. What was the concentration of Pb2+ in the original wastewater
sample?
1 answer
1 answer