Question
The variance σ2X=⟨(X^−⟨X^⟩)2⟩ of an operator, X^, is a measure of how large a range its possible values are spread over (the standard deviation is given by σ=σ2−−√). Suppose that |X⟩ is an eigenstate of some operator X^, what is the variance of X^ in this state? You may assume that |X⟩ is normalized (⟨X|X⟩=1).
Note that the expectation value of an operator in the state |ψ⟩ is given by ⟨O^⟩≡⟨ψ|O^|ψ⟩.
Note that the expectation value of an operator in the state |ψ⟩ is given by ⟨O^⟩≡⟨ψ|O^|ψ⟩.