V^2 = Vo^2 + 2g*h
(Vo/2)^2 = Vo^2 + 2g*h
Vo^2/4 = Vo^2 - 19.6*5
Vo^2/4 = Vo^2 - 98
Multiply both sides by 4:
Vo^2 = 4Vo^2 - 392
4Vo^2 - Vo^2 = 392
3Vo^2 = 392
Vo^2 = 130.7
Vo = 11.43 m/s.
hmax = (V^2-Vo^2)/2g
h max = (0-11.43^2)/-19.6 = 6.67 m.
A ball is thrown straight upward. At 5.00 m above its launch point, the ball’s speed is one-half its launch speed. What maximum height above its launch point does the ball attain?
1 answer