Asked by Anonymous

John has used a solar simulator setup to measure the relation between the voltage and the current of a small photovoltaic cell (40 cm long and 40 cm wide). The measurement setup maintains the standard measurement conditions: the temperature is controlled to 25oC, the incident spectrum is the AM1.5 spectrum and the incident power density is 1000W/m2. The result is illustrated in the figure below.



Calculate the short-circuit current density (in mA/cm2).


John determined that the maximum power he could get out of this module is 19.5 W. Calculate the fill factor of the module (in %).


What is the efficiency of the module (in %)?


John decides to connect two of these modules with strips. This results in an additional 2mΩ series resistance loss. Which is the new fill factor (in %)? (Hint: use the voltage drop at the maximum power point).

Answers

Answered by a
first answer is 25
Answered by Anonymous
Can you also give the rest of the answers?? thanx
Answered by Anonymous
Help on the rest???? Thanks
Answered by Anonymous
None of the other answers are 6...
Answered by Jesus
Someone can give me a hand?
Answered by Sason
second answer: 81.25
third answer: 12.187
Answered by Jesus
Just need the last one now....Someone???? the fourth answer
Answered by Jesus
someone can help???
Answered by Ratan
4th ans is 62.
Answered by UNO
Solar simulators are used to study the performance of solar cells in the lab. In the figure below (left picture), the spectral power density of a solar simulator is shown with the blue line. The spectral power density of this solar simulator is given by:

P(λ)=7.5∗1015λ−2.25∗109 [Wm−2m−1] for 300nm<λ<500nm

P(λ)=2.25∗109−1.5∗1015λ [Wm−2m−1] for 500nm<λ<1500nm

Where the wavelength λ is expressed in meters.



a) calculate the irradiation I of the solar simulator (in Wm−2 )

incorrect
b) What is the photon flux of the solar simulator (in 1021m−2s−1)?

Answered by nt
Hi Ratan how did get 62 for the 4th answer?
Answered by Anonymous
1. 25
2. 81.25
3. 12.187
4. 62
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