A small steel ball rolls off a table (1 meter high) with a speed of 2 m/s. Where should they place a can (15 cm high; diameter 10 cm) to catch the ball?

Answer 1

Xo = 2 m/s.

h = 0.5g*t^2 = 1 m.
4.9t^2 = 1
t^2 = 0.204
Tf = 0.452 s. = Fall time.

Dh = Xo * Tf = 2m/s * 0.452 = 0.904 m =
Hor. distance from table.

d = Dh - r = 0.904 - 0.05 = 0.854 m
= Hor. distance from table.