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A solution is labeled 85.6 g HCl per 480 g of water,calculate the molality and % HCl by wt.
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Answered by
DrBob222
mols HCl = 85.6g/36.5 = about 2.34
m = mols/kg solvent= 2.34/0.480 = ?
%HCl w/w = [(g HCl)/(gHCl + gH2O)]*100
m = mols/kg solvent= 2.34/0.480 = ?
%HCl w/w = [(g HCl)/(gHCl + gH2O)]*100
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