Question
A solution is labeled 85.6 g HCl per 480 g of water,calculate the molality and % HCl by wt.
Answers
DrBob222
mols HCl = 85.6g/36.5 = about 2.34
m = mols/kg solvent= 2.34/0.480 = ?
%HCl w/w = [(g HCl)/(gHCl + gH2O)]*100
m = mols/kg solvent= 2.34/0.480 = ?
%HCl w/w = [(g HCl)/(gHCl + gH2O)]*100