An 8.3 uF and a 2.9 uF capacitor are connected in series across a 24 V battery. What voltage is required to charge a parallel combination of the two capacitors to the same total energy?

Answer 1

Ct = C1*C2/(C1+C2) = 8.3*2.9/(8.3+2.9) = 2.15 uF

Qt = Ct*E = 2.15 * 24 = 51.6 uC.=Q1=Q2.

Energy=0.5C*E^2 = 0.5*2.15*24^2 =619.2 Joules

Parallel Combination:
Ct = C1 + C2 = 8.3 + 2.9 = 11.2 uF.

Energy = 0.5*Ct*E^2 = 619.2 Joules
0.5*11.2*E^2 = 619.2
5.6E^2 = 619.2
E^2 = 110.6
E = 10.52 Volts