You really need to watch the caps. Is that I^- and H^+? If so, then
a.
(1.000-0.868)/(3*10)= ?
b. rate H^+ = rate I^- x (2/3) = ?
H2o2+3i+2h -----> I3+2H2o
In the first 10.0 second of the reaction the concentration of I dropped from 1.000M to 0.868M
a) calculate the average rate of reaction for iodine in this time interval.
b) Determine the rate of change in the concentration of H during this time interval.
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