Wc = m * g = 25.4kg * 9.8N/kg = 249 N.=
Weight of cart.
Fap*cosA-Fk = m * a
Fap*cos30.6 -0.7*249 = m*0 = 0
Fap*cos30.6 = 174.3
Fap = 174.3/cos30.6 = 202.5 N. = Force
applied.
Work = Fap * d = 202.5 * 18.4 = 3726 J.=
3.726 kJ.
A cart loaded with bricks has a total mass
of 25.4 kg and is pulled at constant speed by
a rope. The rope is inclined at 30.6
◦
above
the horizontal and the cart moves 18.4 m on
a horizontal floor. The coefficient of kinetic
friction between ground and cart is 0.7 .
The acceleration of gravity is 9.8 m/s
2
.
How much work is done on the cart by the
rope?
Answer in units of kJ
1 answer