Question

The electron-volt, eV, is a unit of energy (1eV = 1.602 ·10–19 J, 1 MeV = 1.602 ·10–13 J). Since the unit of momentum is an energy unit divided by a velocity unit, nuclear physicists usually specify momenta of nuclei in units of MeV/c, where c is the speed of light (c = 2.998 ·108 m/s). In the same units, the mass of a proton (1.673 ·10–27 kg) is given as 938.3 MeV/c2. If a proton moves with a speed of 7500 km/s, what is its momentum in units of MeV/c?

Answer 1

m = 938.3 MeV/c^2

v = 7500 km/s

m v = 938.3 MeV/c^2 7500 km/s =

938.3 MeV/c (7500 km/s)/c =

23.47 MeV/c

Answer 2

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