Question

We will carry out some steps of the quantum factoring algorithm for N=91

(a) What is the period k of the periodic superposition set up by the quantum factoring algorithm if it chooses x=8? I.e. what is the period of f(j)=8j(mod91)
(b) Using your answer to (a), find a nontrivial square root of 1(mod91). Write your answer as an integer between 0 and 91.
(c) Then, the algorithm proceeds by computing gcd(91,y) for some y. What is y? If there are multiple correct answers, provide any one of them.

Answer 1

anyone,
please answer this.

Answer 2

yes please..

and can anyone help with problem 1e?

Answer 3

In q7 and 8 does all parts need to be correct... can anyone help please

Answer 4

for 1e-I had XZ was wrong..sorry!

Answer 5

does anyone know how to do q7? it seems this question requires all entries to be correct... have only 1 option left now?

Answer 6

I have all the solutions for ans. 5

Answer 7

5A) -1/sqrt(K), -1/sqrt(K)
5B) -1, 0
5C) 1/sqrt(K), 1/sqrt(K)

Make sure you enter the K as uppercase.

Please post whatever answers you get as well.

Answer 8

2) pi

Answer 9

Any one problem 6???

Answer 10

@Naren thanks for Q5.
Q6(a) is 4..

Answer 11

hi again... managed to do b... 64...
can anyone help with C... my last option left... plus q7 & q8 please

Answer 12

1(e)answer :z

Answer 13

Q6c and Q7, Q8 please!

Answer 14

3b and c please!
3d is no

Answer 15

3b - C
3c - 0

Answer 16

thx :)

Answer 17

6c can be calculated by answer to 6b - 1

Answer 18

6(b):64
6(c):63

Answer 19

Q1, 7 and 8 please!

Answer 20

1(a):z
1(b):x
1(c):x
1(d):z
1(e):z
1(f):x,x

Answer 21

Thanks a lot

Answer 22

Q4 please!

Answer 23

4(a):-1 4(b):4
4(c):last option

Answer 24

Q:7&Q:8
PLEASE

Answer 25

Q 7 and 8 Please!!!

Answer 26

Q7 and 8 please

Answer 27

8a) theta=pi/3 and phi=0. this is 100% right. thanks guys

Answer 28

what about others, please help rs and others..........

Answer 29

In this problem, assume that we are working in units such that ℏ=1. When providing Bloch sphere coordinates, please ensure that 0≤θ≤π and 0≤ϕ<2π whenever applicable.

8(a) Consider a spin qubit in the state 3√2|0⟩+12|1⟩. What are the coordinates (θ,ϕ) of this qubit on the Bloch sphere?
θ=?
ϕ=?

8b. We turn on a magnetic field in the z^ direction at time t=0. This corresponds to the Hamiltonian H=BZ, where B is a constant and Z is the usual phase flip. What is the state of our qubit at time t as a function of B and t?

8c. What are the coordinates (θ,ϕ) of this qubit on the Bloch sphere at time t, as a function of B and t?

8d. Now suppose we start with the qubit |ψ(0)⟩=|0⟩ and we apply a magnetic field in the x^ direction at t=0. This corresponds to the Hamiltonian H=BX, where B is a constant and X is the usual bit flip gate. What are the coordinates (θ,ϕ) of this qubit on the Bloch sphere at time t, as a function of B and t?
θ=?
ϕ=?

Answer 30

Please 7 and 8b 8c 8d

Answer 31

anyone can help me with Q7 and 8b,c, d please.
Thanks for all who are trying to help each other.

Answer 32

hi, what about 1)d) it has two parts? which one is z and what is the other one?

Answer 33

@rs both parts are Z...
Do you have answer for q7 or 8

Answer 34

Thanks, I am working on 7 and 8. I have already posted for 8a). will post the rest as soon as it is done

Answer 35

on 7B answer is 2, ?, 8
Please i have the last submission to find out what insyead of "?". hope i helped you guys

Answer 36

Thanks rs!

Answer 37

@needhelp ... how did you get 2, and 8

Answer 38

@Need help its 2, 9/2, 8.
do you have answer for q7a and C please..thanks

Answer 39

anyone help please with q7(a)

Answer 40

8D please!

Answer 41

7A: momentum values 2, 3, 4
State for 3 is (0 1 0)
Got the seemingly correct values for 2
(1 0 -i) and for 4 (1 0 i), but the system does not accept them.

Answer 42

7A: momentum values 2, 3, 4
State for 3 is (0 1 0)
Got the seemingly correct states for 2
(1 0 -i) and for 4 (1 0 i), but the system does not accept them.

Answer 43

Great to see constructive collaboration here. I have got the same questions as most of you here. I do not have 3A; 7A, 7C; 8B, 8C, 8D. Can anyone help me out with these?

I see that someone is working on 7A. I will keep trying as well!

Answer 44

3A - (-1)^x<i> - middle answer
8C - pi/3; 2*B*t</i>

Answer 45

Thanks for your help guys... what is q8(b. struggling with 7 as well.

Answer 46

Oy,

8b:
e^(-i*B*t)*sqrt(3)/2
e^(i*B*t)/2

Do not tell anyone that I betrayed to you this great secret.

Answer 47

Can anyone help with 8d and q7

Answer 48

thank you for the secret friend!!!

Answer 49

7B, again: 2, 9/2, 8.

7A: momentum values 2, 3, 4
State for 3 is (0 1 0)

Don't have anything more.

Answer 50

Anyone done 8D? Please, I'm stuck there.

Answer 51

7c, t=pi --> -1,0,0

Answer 52

Thanks "a" ..can you help with Q7(a)

Answer 53

7C complete answer:

0 0 1

-1 0 0 - pi rotation around x axis,
|z> -> |-z>

Answer 54

Thanks...anon @4:37pm, can you also help with Q7A.. thanks

Answer 55

anyone can help me with Q7a and 8(d)..thanks...

Answer 56

I AM 90% SURE THAT THE ANSWER TO 8D IS:

theta: -2*B*t
phi: pi/2

CAN ANYONE PLEASE VERIFY THIS? I HAVE ONLY 1 CHECK LEFT...

Answer 57

Yeah, that's not it the theta: -2*B*t
phi: pi/2 is wrong.

Answer 58

It could be because -2*B*t is not in the [0,2*pi] range. Maybe it's theta = (2*pi - 2*B*t) instead.

Anyone willing to try that?

Answer 59

any other guesses?

Answer 60

I tried 2*pi-2*B*t and pi/2, it was wrong :(

Answer 61

7A:
1/sqrt(2) , 0, -i/sqrt(2)
2
----
0 , 1, 0
3
----
1/sqrt(2), 0, i/sqrt(2)
4
-------
Any update on 8D?

Answer 62

for 8d i tried with this but got wrong
theta=2*B*t phi= 0 or pi/2 or pi

Answer 63

8(d)
I tried everything... I can't get any value for 0<=thetha<=pi

Answer 64

8(d)
the answer should be
thetha = -2*B*t
phi = pi/2

I tried thetha = -2*B*t, 2*pi-2*B*t (although this mayn't be always between 0 and pi), 2*B*t (i know its wrong but i tried)

Answer 65

The 8D answer with theta=-2*B*t and phi=pi/2 is wrong!

Answer 66

Yes, I was trying to say it should be the answer, but the question required 0<=thetha<=pi...
this doesn't satisfy for any answers mentioned above by me...

I feel this question is tricky... can someone find the answer?

Answer 67

Shouldn't the answer for 8d be as theta = pi/2 and phi = -2*B*t ? Can you confirm?

Answer 68

@Anonymous. That is not the answer; That is the same one I had got when I last tried. I've got 2 attempts left now.

Answer 69

can anyone help with Q8d please!

Answer 70

theta = pi (8D)

Answer 71

theta = pi
phi = pi/2
is wrong Jerome! How did you get theta = pi ??
I'm down to one try, so wait for a genuine answer for 8D

Answer 72

Jerome, did you check the answer ?

theta=pi

What is phi then? 2*B*t ?

Answer 73

Im certain theta is correct, unsure about phi. it is not -B*t or -2bt. try 2bt

Answer 74

hi guys... have you got answer to Q8d.. I have now one option left only

Answer 75

Jerome, did you try ? Both answers must be correct in order to get check marks on both.

Answer 76

i tried theta = pi and phi = -b*t
and theta = pi and phi = -2*b*t

try it with 2bt

Answer 77

I tried:

theta = pi phi=-B*t
theta = pi phi=-2*B*t

Both incorrect. Down to the last answer.

Answer 78

Could someone try:

theta = pi phi= 2*B*t ?

Answer 79

8d) Theta = pi
Phi = 2*b*t

Answer 80

Jerome, is this correct? I think somebody tried it and reported as incorrect, though the answer makes sense: X converts |0> to |1>, and 2*B*t is phi for |1>

Answer 81

Did anyone try

8d) Theta = pi
Phi = 2*b*t ?

Answer 82

wrong

Answer 83

jerome wrong any one got answer for 8D

Answer 84

theta = pi
phi = 0

Answer 85

For 8d.
Theta = pi
Phi = 0

Answer 86

I just tried what Jason said and it worked :)

Answer 87

I have helped with answers ...can someone help me with 8d...down with one option...I think both parts need to be correct...

Answer 88

pi and 0 work for 8d :)

Answer 89

I tried theta=pi and phi=0 its wrong!!!

Answer 90

Also tried theta = pi and phi = 0, its wrong. Anyone have any idea for 8d?

Answer 91

I tried what Jason said is working long time ago. It is wrong. I don't understand how it could have worked for you. Are you trolling ?

Answer 92

He must be trolling, lets ignore what jason and jerome say!

Answer 93

BTW, both parts must be correct.

Answer 94

What is the answer?! Someone make another question

Answer 95

please help with q8d please

Answer 96

can anyone help me with 8d please!!

Answer 97

It seems like some people experimenting at the expense of the others. A guy does not want to waste his trial, so he posts an answer he thinks is right as the correct answer. Then, he gets the feedback from those who unwittingly used their trials. Very mean, I say.

Answer 98

I think the answer is:
theta: pi/2
phi: (2*pi)-(b*t)

Answer 99

Only got 1 try, someone try that ^^^

Answer 100

Jason and Jerome please help with q8d!

Answer 101

@ Anonymous at 4:24pm

Your thinking is great. But did you try it? If not, why do you want the others to try? Could you give some background for your thinking ?

Answer 102

Jason and Jerome are as much in darkness as we are.

Answer 103

theta=pi/2 and phi=2pi-bt is wrong!!

Answer 104

to those who have answers to Q8D..please can you help with explanation or your thoughts..thanks

Answer 105

8D- Answer
theta = pi
phi = (2*pi)-(B*t)

You are all welcome :)

Answer 106

for pi and 0: X maps 0 to 1, meaning theta = pi. If it is at 0 or 1, then phi is irrelevant, could be 0, because 0 and 1 are along Z axis.

Answer 107

No the answer is:
theta = pi/2
phi = 0

Answer 108

Anon @ 5:13 - is it another bogus answer ?
What is the rationale for your answer ?

Answer 109

@ Anonymous at 5:17:

BS, tried that long ago, wrong!

Answer 110

As another anomyous @5:16 said, the answer would be theta = pi and phi= 0

Answer 111

help withq8d please someone out there!!!

Answer 112

The answer for 8d is theta = pi and phi = 0!!!!!

Answer 113

pi/2 and 0 are wrong!

Answer 114

Sorry about the mistake earlier i copied down the wrong answer, that was an answer from a previous attempt. The correct answer has already been stated on here.

Answer 115

Anonymous @5:44 PI is correct NOT pi/2

Answer 116

pi and 0 is also wrong!!

Answer 117

@Jerome ..what is the correct answer please!

Answer 118

@ Anonymous at 5:49:

He doesn't have a clue! He is just trolling...

Answer 119

@Jerome..can you atleast explain how to get the answer please

Answer 120

Using the formula for the state psi under the act of a hamiltonian, you deduce that theta = pi and psi = -bt. However the -bt needs to be changed. think about why it needs to be changed

Answer 121

so is theta=pi and phi=2pi-bt

Answer 122

anyone please help with 8d..

Answer 123

theta=pi and phi=2pi-bt ISN'T WORKING

Answer 124

@Jerome thanks for the explanation so is the answer pi and 2pi-bt.. thank you

Answer 125

thanks @anon @7.09pm it also doesn't work for theta=pi and phi=2pi-2bt...
HELP!!

Answer 126

please help with 8d.

Answer 127

Jerome give the answer please!!

Answer 128

Just wondering has anyone got the answer for q8d..or am I the only one banging my head!!

Answer 129

help with q8D

Answer 130

did anyone already check for phi=2bt or 2b

Answer 131

Ive checked and its neither phi=2bt nor 2b

Answer 132

The answer is in both cases 0 and 0

Answer 133

No but almost! Pi and 0 works! Job done!!

Answer 134

pi and 0 does not work. Was tried long time ago. I doubt that 0, 0 would work either.

Answer 135

Jason, please stop trolling with your pi and 0 guano.

Answer 136

anyone plz try with 0 , 0
mine no chance left

Answer 137

@jason wonder did you really got the answer????????

Answer 138

Why not try yourself or insted give up? Only 4 points in a final exam of a whole course? Does it matter to get the Certificate? Is it so important? I assume that if you have been cheating the whole course doesn't matter not to get a 100% mark. Any explanation? If somebody gives a good explanation, I promise to give the correct answer.

Answer 139

ya okay maybe some people have cheated all the way through. But there may be a reason or so either to pass atleast the 80% mark because it is high cutoff and we have limited chances. Y people may do this?
To get certificate . Does certificate matters? Yes, may be they will use it in college to show off their intelligence or may be needed for some recommendation or will help them in some way....
There might be reason they can't solve all the problems infact only some get 100% mark and you wonder how much pass the 80% barrier? They might have wasted their 2 months or so........

Answer 140

We will get the certificate regardless, very well past that point. And we are not cheaters but rather the hard working overachievers. The problem is the suspense - we where studying so hard, what we have not learned so that nobody could answer that seemingly easy question ? What is the trick with that question ? Will we ever know ?
X turns |0> into |1>. So, theta is pi. Phi is the angle in the complex plane that is orthogonal to Z / -Z axis where |0> and |1> lie. So, phi is not relevant. It could be 0, or anything.
Do you disagree with these conclusions ? Do you see any mistake ?

Answer 141

sometimes you have to do wrong things to get into the right way may be for a cause or so

Answer 142

BTW, it is meaningless to talk about cheating in this course. The problems are not authentic. They are taken from a set of quantum mechanics/ quantum computing problems that is moving from a course to a course. Some "non-cheaters" had no quarrel with the course because they have the answers to that set. So, we are just equalizing. Equal opportunities, that is the slogan.

Answer 143

@MMM you are correct!!!!!!!!

Answer 144

I bet "Cheaters" don't have answer to this question...

Answer 145

I think the answer is 0 & 0

Answer 146

They will both be 0 because X is perpendicular to z so the field doesn't effect it. The transformation by X doesn't either because it is still around the z axis.

Answer 147

@jerome are you sure?

Answer 148

Yes

Answer 149

0, 0 is wrong.

Answer 150

Jerome you are wrong, I think you also don't know the right answer. Stop fooling us around

Answer 151

Jerome is fooling you.

The actual answer is pi, pi. Jerome, go home.

Answer 152

pi,pi seems to be wrong too.

Answer 153

Yup pi, pi is also wrong

Answer 154

Oh come on! pi pi/2. It is so eeeeeeeasy to see :D

Answer 155

Nope, pi and pi/2 also wrong.

Answer 156

Ha ha! Correct answers told as wrong. The good answer was already given and now the question: who is fooling who?

Answer 157

plz tell what is the answer?

Answer 158

The answer, my friend, is blowin' in the wind, the answer is blowin' in the wind.

Answer 159

there are various answers and only 2 chances, what you think will be the probability?

Answer 160

0<p<1, or something like that

Answer 161

P-->0

Answer 162

come on please please please please please please please please please tell the right answer

Answer 163

Since phi is irrelevant, you must leave it blank. The grader is intelligent and will mark it as correct.

Answer 164

what nonsense is this? if you so intelligent then what is theta?
i have never seen not putting any value and getting it correct

Answer 165

Well try it and you'll see.

Answer 166

so atleast tell what is theta?
if you r right i would worship you

Answer 167

OK, theta is f*a*r*t/2

Answer 168

This is a special optimization question.
You just leave both fields blank and click submit. The grader will figure the correct answer for you for theta, and will simply mark the blank phi as correct.
try this!

Answer 169

what are f, a & r ???

Answer 170

You know where it is coming from, don't you?

Answer 171

nope!!!!!!

Answer 172

you are wrong this too :D :D :D

Answer 173

@Jerome stop being mean, if you can help that's fine if cant please don't confuse us!!!

Answer 174

theta = pi
phi = 0
got 100%

Answer 175

pi and 0 is wrong...I wonder how you got 100%

Answer 176

it is not wrong, do not fool around

Answer 177

0 and 0 is wrong!

Answer 178

I checked 0 and 0 its marked wrong!

Answer 179

final ans of 8D plzzzzzz!!!

Answer 180

@quantum...I have checked and it was wrong...you stop fooling around mate!!!thanks for yr sharing anyway!

Answer 181

You're welcome. Does this mistake made you don't pass the course? Come on... is this the case?

Answer 182

@ quantum.. actually I passed ... even if you have 100% does it matter! have some self pride mate!!

Answer 183

so you admit you put the wrong answer on purpose!!! don't you feel guilty quantum?

Answer 184

don't feed the troll ;)
back to topic.. I have two submissions left but no more ideas..

Answer 185

I am working on an idea! Anonymous @4:33pm wait for me to answer again and then try it for me please :)

Answer 186

what's your idea @4H34 ?

Answer 187

Have to change |0> to |+> and |-> equivalents and then simplify from there on in.

Answer 188

@quantum I am pretty sure you must have used one of our answers at some point in this course!! you know what... no one is perfect!!

Answer 189

annon 234, why that ?

Answer 190

@4:46 because the X bit flip acts in those eigenvectors.
I think the answer is as follows:
theta = pi/2
phi = B*t

Now i am not 100% on phi; it may be 2*B*t

Answer 191

Phi would be 2*B*t!!!

Answer 192

Wrong !!!! I try it!!

Answer 193

@234, havn't tried, only one try left

physics.stackexchange dot com/questions/81101/quantum-computation-hamiltonian

maybe some hints

Answer 194

@ anyone... can anyone help with Q8D please!!!

Answer 195

pi/2 B*t and 2*B*t were tried long time ago, and failed. Anons 234 idea about conversion of |0> to |+> / |-> basis was tried and yielded e^(2Bt)|1>. The grader does not take that answer equivalent to pi 2Bt.

Answer 196

@ Jerome...why are you even here when you have the right answer!!1

Answer 197

@ Jason and Jerome does not have any clue...check new postings guys and don't be fooled!

Answer 198

it seems now that the answer is very simple... but what is it?

Answer 199

I am incredibly close to the answer. Will update soon!

Answer 200

pi/2 and Bt is wrong guys...just tried... down to my last option... help!

Answer 201

guys don't trust anyone..trust yr instincts...

Answer 202

The answer is theta = 0 and phi = 2pi !!!!
I can leave this question forever now!!

Answer 203

No....

theta=0 and phi=2*pi

Answer 204

Theta=2BT
Phi=pi/2

Answer 205

Thankyou Anonymous @ 7:08 it worked

Answer 206

theta = 2bt
phi = 0

Answer 207

which one is right: theta: 2Bt and pi/2 or 2bt and 0!!! please help!!

Answer 208

Theta=2BT
Phi=pi/2

Answer 209

It works at last!

Answer 210

really it doesn't and did not work for me mate!!

Answer 211

No, it is not. All troll answers are wrong.

Answer 212

seriously anyone has any help to offer for q8d

Answer 213

help please with q8d

Answer 214

what works guys for 8d

Answer 215

For $1000, I'd give you the right answer.

Answer 216

done
but if it is wrong we would take 1000 from you

Answer 217

So, are you ready to transfer them to my personal account at the Bank of Nigeria ?

Answer 218

Time is running out for you. No money means no score sufficient to get the certificate.

Answer 219

The answer is theta = 0 and phi = 2Bt
everyone stop being mean to the people who want the answer

Answer 220

yup,
1000 USD done......

Answer 221

Theta is not 0 and phi is not 2*B*t

Answer 222

jason what happened?

Answer 223

seems you are doing a nice deal out here

Answer 224

Confirmation of theta = BT and Phi = pi/2

Answer 225

you asking us to confirm or telling the answer?

Answer 226

sorry theta = 0, not bt!
theta = 0 and hphi = pi/2

Answer 227

are you sure???
i will give jason's deal to you

Answer 228

I am fairly certain that it is

Answer 229

can you explain how you got theta = 0 and phi = pi/2

Answer 230

did you try it?

Answer 231

So, phi = pi/2 always, independent on time and the strength of the field ?
H-m-m, maybe, maybe, because the perpendicular field separates the spin upwards/downwards. Though, I'm still skeptical.

Answer 232

Citation:
"How can we create a beam of qubits in the state ψ=0? Pass a beam of spin-1/2
particles with randomly oriented spins through a Stern-Gerlach apparatus oriented along the z axis. Block the downward-pointing beam, leaving the other beam of 0 qubits.

Answer 233

you try it and send us a screenshot of you r page

Answer 234

Guys, simply read this, pages 2 & 3

inst.eecs.berkeley.edu/~cs191/fa07/lectures/lecture15_fa07.pdf

Answer 235

theta = 0 and phi = pi/2 is wrong
theta = pi/2 and phi = 0 is also wrong

Answer 236

So, here is my rationale. |+> and |-> are two eigenvectors of X, with eigenvalues of 1 and -1. So, putting them through X makes them unchanged, bar reversal of |->.
|0> = 1/sqrt(2)|+> + 1/sqrt(2)|->

That is the output:

X*|0> = |1> = 1/sqrt(2)|+> - 1/sqrt(2)|->;

Canonical form:

Psi(x) = cos (theta/2)+ e^(i*phi)sin (theta/2):

Now, how do we get from canonical form to |1> output ?

Easy:
theta/2 = pi/4, thus theta = pi/2;
e^(i*phi)= 1 iff phi = 0

So the answer should be theta = pi/2
and phi = 0.

Generally speaking, the magnetic field performs Bloch sphere rotation/transposition along the axis it is applied. Therefore, application along x axis transforms |0> into |1>

I don't remember if theta = pi/2
and phi = 0 was ever tried. But, rationally, that should be the answer.

P.S. I cannot try, down to the last submission.

Answer 237

I see above that theta = pi/2
and phi = 0 were tried. Maybe, the grader is not programmed it correctly ? Did anyone really got his 8D answer accepted?

Answer 238

if you so sure please risk yourself and tell us

Answer 239

Theta = 2bt
Phi = 3pi/2

Answer 240

Found the same result but don't beleive in it. ;)

Answer 241

@chop are you sure???

Answer 242

I am quite sure

Answer 243

No. I'm not sure. Really. Looks like it's wrong result.

Answer 244

Fake @chop detected!

Answer 245

what is going on????

Answer 246

theta = 2bt
phi = pi

Answer 247

what is phi tell properly

Answer 248

phi is pi!!

Answer 249

did you got it correct?

Answer 250

Yes i did.

Answer 251

could you send a screenshot of it????

Answer 252

Cant send screen shots on here :/

Answer 253

take a screen shot and upload on bit and paste the link without h-t-t-p if u r confident about your answer and your intelligence

Answer 254

i.minus dot com/i5xld8aUe08Ee.png

I CAN

Answer 255

ya good screenshot is of wrong answer

Answer 256

anyone confident of answer please send screenshot

Answer 257

Theta = 2bt
Phi = pi/2

imgur dot com/eMrPvfk

Answer 258

Jerome - fake! fake screen shot!

Answer 259

@jerome yup its fake

Answer 260

YEap, if you see this thread, you will see that they ask if someone has mixed phi with theta as he give an answer Theta=pi/2 a Phi=2bt. It's only matter of reading you cheaters.

physics.stackexchange dot com/questions/81101/quantum-computation-hamiltonian

Answer 261

@anonymous please try and send a fake screenshot

Answer 262

Theta=pi
Phi=s*o*B

Answer 263

@jerome

i.minus dot com/i9iaY1QUADBkO.png

You managed to fail your fake... congrats.

Answer 264

please help if you can with Q8d

Answer 265

Hi guys... I just tried:8d
theta: 2*B*t and phi: 3*pi/2 and it worked!!
thanks to those who helped...

Answer 266

@Pari. Another fake ? Where did you get theta: 2*B*t and phi: 3*pi/2 from ?

Answer 267

Yah fake too :(

Answer 268

No, it is real, though I forgot the sign:
theta: -2*B*t and phi: 3*pi/2

Answer 269

fake

Answer 270

there is no point in faking when you can always create a new account and get an extra 3 tries(I hope you guys aren't trying these on your actual accounts).

Why not just stick to solving the problem.
I'm trying to do it like I did 8C but it's just not working.
The rotation about the x-axis changes phi to theta and theta to phi.

Answer 271

My answer is correct...take it or leave it ...Q8d theta:2*B*t and phi 3pi/2..stop using my name...and confusing others...guys trust me... and stop This is my last post... anyone using pari is fake!!!I am going to report those using my name!!

Answer 272

thx Pari :)

Answer 273

Fake again...

Answer 274

fake Pari, or whatever it was, fake answer.
If you claim you are real, explain how you arrived to that answer, pleeeeazeee

Answer 275

I tried theta = 2*B*t and phi = (3*pi)/2
AND IT WORKED

THANKYOU SO MUCH Pari!!

Answer 276

ss01, is theta= 2*B*t or -2*B*t?

Answer 277

Its 2*B*t

Answer 278

YES IT WORKED, THANK YOU GUYS
THETA= 2Bt and phi= 3pi/2

Answer 279

Thanks Pari and SS01...we all know who the fake Pari may be?
so its... theta= 2*B*t and phi= (3*pi)/2
Thanks to also everyone who helped through out!!

Answer 280

i dunno how m stuck with 8c. :(
i need help.

Answer 281

You find the all answers somewhere in this thread:

8:
A: pi/3 0
B: e^(-i*B*t)*sqrt(3)/2 e^(i*B*t)/2
C: pi/3 2*B*t
D: 2*B*t 3*pi/2

Thanks a lot for 8D

Answer 282

Thanks Pari. Still, I wonder, how did you arrive to the correct answer? Seems that I missed something in the course.

Answer 283

"why are you faking ..."

I'm a TA. It was entertaining to observe you cheating. So, we have decided that those of you who entered the answer within 6 hours after publication on this site will not get a completion certificate, because of academic dishonesty. The dishonesty policies and the conditions for the course completion were published rather prominently on the course site. Cheating in EDX courses will not be tolerated.

Answer 284

How will you find out who gave the answers by cheating and who actually solved each answer.

Some of us actually solve the answers out on paper and plug it in to the autograder.
A few of us haven't even shared a single answer and were just here for entertainment purposes.

I think you are either trolling or bluffing. Have fun with the complaints from test-takers who entered answers correctly.

Answer 285

We have your IP addresses. If you visited the page for "entertainment purposes", and then entered the answer stated on this page within 6 hours after your visit, you clearly cheated. Since the "entertainment purposes" of your visit included the forbidden collaboration on the problems, you violated the terms of the course, and you will receive no certificate.

Answer 286

thnx frnds, all of you :-)

Answer 287

Your method of using IP addresses would never work. Most people here have static Ip's ,unless you have a corporate connection; everyone's IP address would change the moment they restart their modem.

Obtaining the Ip address for each comment here is clearly impossible.This site does not store ip addresses and attempting to find it is illegal.

I would have to report you for performing illegal acts on behalf of EdX.

Performing such a task of filtering IP addresses on Edx's server would require admin access to the server files which you don't have and can not get because you would have to be the admin.

I don't care about the certificate; just wanted to learn. If you are confident you can find IP addresses for every person then do so and tell me which country I live in. troll.

Answer 288

You don't understand how it works. You will be up to an unpleasant surprise, cheater. If you took the course just to learn, you had no business to cheat. As Mark said, the final exam was very straightforward if you studied in earnest. Since you had to resort to cheating, it appears that you have not learned much.

Answer 289

I discourage cheating, I haven't even given the final exam, I'm just auditing the course. (just to learn)
I'm just proving that your ideology and methodology is wrong. You could really mess up the EdX system if you decided to do it your way.

You can't see what visitors were seeing before visiting your website(EdX). Having the Ip address would mean nothing since you can't view visitors' browsing history.

I still challenge you to find what country I'm in (I don't care if you get all my ISP's details; I'll just restart my modem). If you can do it, then I'll back out and let you proceed while I make better use of my time.

Answer 290

You let me to proceed ? That is most interesting. Thank you, sahib, I'm patiently waiting for your kind permission.

Answer 291

Love the sarcastic comment. This is the best entertainment I've received throughout the entire duration of this publication.