Asked by Jacky
A certain personality index postulated by Professor Bailey is normally distributed, with a mean of 0.4 and a variance of 0.0004. What is the probability that the Professor Bailey’s personality index of a randomly selected person will exceed 0.44?
Answers
Answered by
PsyDAG
Z = (score-mean)/SD
variance = SD^2
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
variance = SD^2
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
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