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Complete combustion of 8.00 g of hydrocarbon produced 26.0g of CO2 and 7.99g of H2O. What is the empirical formula for the hydr...Asked by Anonymous
Complete combustion of 8.80 g of a hydrocarbon produced 27.1 g of CO2 and 12.5 g of H2O. What is the empirical formula for the hydrocarbon?
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Answered by
DrBob222
Convert mols CO2 to mols C. That's 27.1/44 = ?
Convert mols H2O to mols H. That's 12.5*2/18 = ?
Now find the ratio of C to H with the smaller number being no less than 1.00. The easy way to do that is to divide the smaller number by itself (thereby assuring you of getting 1.00 for that one) and find the empirical formula.
Convert mols H2O to mols H. That's 12.5*2/18 = ?
Now find the ratio of C to H with the smaller number being no less than 1.00. The easy way to do that is to divide the smaller number by itself (thereby assuring you of getting 1.00 for that one) and find the empirical formula.