Asked by Miranda

A ball rolling down a hill was displaced at 19.6m while uniformly accelerating from rest. If the final velocity was 5.00 m/s what was the rate of acceptation?

12 years ago

Answered by Henry

a = (V^2-Vo^2)/2d
a = (5^2-0)/39.2 = 0.6378 m/s^2.

12 years ago

Answered by bisky

3.5 m/s root 2

8 years ago

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