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A ball rolling down a hill was displaced at 19.6m while uniformly accelerating from rest. If the final velocity was 5.00 m/s what was the rate of acceptation?
11 years ago

Answers

Henry
a = (V^2-Vo^2)/2d
a = (5^2-0)/39.2 = 0.6378 m/s^2.
11 years ago
bisky
3.5 m/s root 2
7 years ago

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