Asked by Mario

Mario, a hockey player, is skating due south at a speed of 6.6 m/s relative to the ice. A teammate passes the puck to him. The puck has a speed of 12.9 m/s and is moving in a direction of 23° west of south, relative to the ice. What are the magnitude and direction (relative to due south) of the puck's velocity, as observed by Mario?
Answered by Elena
v(south) =12.9cos23 -6.6 =5.27 m/s
v(west) =12.9sin23=5.04 m/s
v=sqrt{v(west)²+v(south)²} =
=sqrt{5.04²+5.27²} =7.3 m/s
tanα =5.04/5.27 =0.95
α=43.7º
Answered by Mukelo
Why was the 6.6 subtracted because it's in the same direction as the 12.9cos23 vector?
Answered by Mukelo
Why are the south velocities subtracted because they are in the same direction?
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