Asked by Nahar
A man walked into the road at 4 miles per hour and returned over the same road at the rate of 3 miles per hour. If he completed the entire trip in 7/2 hours,how far in miles in to the roads did he walk?
Answers
Answered by
Reiny
let distance he went each way be x miles
time for first leg = x/4
time for 2nd leg = x/3
x/4 + x/3 = 7/2
times 12
3x + 4x = 42
x = 6
he went 6 miles into the road
check:
time for 1st part = 6/4 hrs
time for 2nd part = 6/3 hrs
and 6/4 + 2 = 3/2 + 2 = 7/2
time for first leg = x/4
time for 2nd leg = x/3
x/4 + x/3 = 7/2
times 12
3x + 4x = 42
x = 6
he went 6 miles into the road
check:
time for 1st part = 6/4 hrs
time for 2nd part = 6/3 hrs
and 6/4 + 2 = 3/2 + 2 = 7/2
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