Asked by Alexus
A saturated solution of potassium chlorate is formed from 100 grams of water. if the saturated solution is cooled from 80 degrees celsius to 50 degrees celsius, how many grams of precipate are formed?
Do you have a table that lists the solubility at 80 and 50 degrees C?
Do you have a table that lists the solubility at 80 and 50 degrees C?
Answers
Answered by
Anonymous
30grams of KCL
Answered by
Hannah Wilson
im sorry idk.
Answered by
Unknown
Subtract 50 from 80, then subtract that from 100
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