Asked by Roy
int cosxsinx dx
Answers
Answered by
Jai
integral cos(x) sin(x) dx
We simply use substitution.
Let u = sin(x)
Thus du = cos(x) dx
Rewriting,
= integral (u du)
= (1/2)*u^2 + C
= (1/2)*sin^2 (x) + C
Or you may also use substitute the formula sin(2x) = 2sin(x)cos(x) to the original, and then directly integrate.
Hope this helps~ :3
We simply use substitution.
Let u = sin(x)
Thus du = cos(x) dx
Rewriting,
= integral (u du)
= (1/2)*u^2 + C
= (1/2)*sin^2 (x) + C
Or you may also use substitute the formula sin(2x) = 2sin(x)cos(x) to the original, and then directly integrate.
Hope this helps~ :3
Answered by
Reiny
Or
following Jai's method.
let u = cosx
etc
to get
(-1/2) cos^2 x + c
following Jai's method.
let u = cosx
etc
to get
(-1/2) cos^2 x + c
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