Asked by Lucy
Which of the following expressions are not equal to 1?
A) sin^2 theta + cot^2 theta sin^2 theta
B) (sin^2 theta/1-cos theta)-cos theta
C) sec^2 theta + tan^2 theta
D) cot^2 theta sin^2 theta/cos^2theta
Answer: D
A) sin^2 theta + cot^2 theta sin^2 theta
B) (sin^2 theta/1-cos theta)-cos theta
C) sec^2 theta + tan^2 theta
D) cot^2 theta sin^2 theta/cos^2theta
Answer: D
Answers
Answered by
Damon
for D I get
c^2/s^2 * s^2 /c^2 = 1 sorry
A gives
s^2 (1 + c^2/s^2) = s^2 + c^2 = 1
B gives (does not make sense the way you wrote it)
Maybe you mean
sin^2 theta/(1-cos theta)-cos theta
[s^2 -c (1-c)] /(1-c)
[ s^2 + c^2 -c] / (1-c)
(1-c) / (1-c)
1
C gives
(1/c^2) + s^2/c^2
= (1 + s^2)/c^2
not 1
c^2/s^2 * s^2 /c^2 = 1 sorry
A gives
s^2 (1 + c^2/s^2) = s^2 + c^2 = 1
B gives (does not make sense the way you wrote it)
Maybe you mean
sin^2 theta/(1-cos theta)-cos theta
[s^2 -c (1-c)] /(1-c)
[ s^2 + c^2 -c] / (1-c)
(1-c) / (1-c)
1
C gives
(1/c^2) + s^2/c^2
= (1 + s^2)/c^2
not 1
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