Asked by Kyle
Minimize F = x2 + y2 with x + 2y = 5
Thank you
Thank you
Answers
Answered by
Steve
F = (5-2y)^2 + y^2
= 25-20y+4y^2+y^2
= 5y^2-20y+25
= 5(y^2-4y+5)
y^2-4y+25 = (y-2)^2 + 21
so has minimum at y=2
so, x=1 and
F(1,2) = 5
= 25-20y+4y^2+y^2
= 5y^2-20y+25
= 5(y^2-4y+5)
y^2-4y+25 = (y-2)^2 + 21
so has minimum at y=2
so, x=1 and
F(1,2) = 5
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